Answer: Choice A) -3
Work Shown:
[tex]\log_{2}(x+7) = 2\\\\x+7 = 2^2\\\\x+7 = 4\\\\x = 4-7\\\\x = -3\\\\[/tex]
Which leads us to choice A. In the second step, I used the rule that [tex]\log_b(y) = x[/tex] is equivalent to [tex]y = b^x[/tex]. For each equation, the b is the base. Note how logs undo exponents and vice versa.
