noellelks
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A 12.0 V battery has as 80.0 Ohm
resistor attached. How much
current flows through the circuit?
(Unit = A)

Respuesta :

  • Potential difference=V=12V
  • Resistance=80ohm=R
  • Current be I

Using ohms law

[tex]\\ \sf\longmapsto \dfrac{V}{I}=R[/tex]

[tex]\\ \sf\longmapsto I=\dfrac{V}{R}[/tex]

[tex]\\ \sf\longmapsto I=\dfrac{12}{80}[/tex]

[tex]\\ \sf\longmapsto I=0.15A[/tex]

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