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15-08-2021
Chemistry

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What is the pH of a 2.50×10^-4 M solution of sodium hydroxide

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15-08-2021

Answer:

Answer is 10.398(approx.)

Explanation:

NaOH ⇄ Na⁺ + OH⁻

pOH = -log[OH⁻]= -log(2.5×10⁻⁴) = 3.602

∴pH = 14 - pOH = 10.3989(approx.)

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