Respuesta :

caylus

Answer:

Step-by-step explanation:

[tex]y^2+6y+8x+1=0\\\\y^2+2*3y+9+8x+1-9=0\\(y+3)^2+8x-8=0\\8x=-(y+3)^2+8\\\\x=-\dfrac{(y+3)^2}{8}+1 \\Vertex=(1,-3)[/tex]

ashishdwivedilVT

The vertex is (1,-3).

To find the the vertex of the parabola.

What is parabola?

A symmetrical open plane curve formed by the intersection of a cone with a plane parallel to its side.,

Given that:

[tex]y^{2} +6y+8x+1=0\\\\y^{2} +2*3y+8x+1+9-9=0\\\\(y+3)^{2}+8x-8=0\\\\8x=-(y+3)^{2}+8\\\\x=-\frac{(y+3)^{2}}{8} +1\\\\vertex=(1,-3)\\[/tex]

So, the vertex is (1,-3).

Learn more about parabola here:

https://brainly.com/question/24390399

#SPJ2

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