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Find the equation of a line that passes through these two points

(3,-4) and (-2,6)

Describe in your own words how you would find the equation of the line

Respuesta :

gwenspooner85

Answer:

y = -2x + 2

Step-by-step explanation:

The equation of a line is y = mx + b.

First we want to find m, the slope. We can used the coordinates to do so: [tex]m = \frac{6-(-4)}{-2-3}\\m = \frac{10}{-5}\\m = -2[/tex]

Now we know that the equation is y = -2x + b. We can plug in the coordinate (3, -4) to find b.

[tex]y = -2x + b\\-4 = -2(3) + b\\-4 = -6 + b\\b = 2[/tex]

So the equation is y = -2x + 2.

kristinafromig

Answer:y=-2x+2

Step-by-step explanation:First enter your points in this equation y2-y1/x2-x1

6-(-4)/-2-3)=10/-5=-2

Then find your y intercept. Choose whatever point but I’m choosing the first one. (3,-4) Plug into y=mx+b

-4=-2(3)+b

-4=-6+b

add 6 to both sides

2=b

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