Answer:
Explanation:
For moment of inertia, the mass will appear as a point mass on the rim of the larger radius.
Total moment of inertia of the system is (I + mR₂²)
torque is FR₁
α = τ/I = FR₁/(I + mR₂²)
a = R₂α = R₂(FR₁/(I + mR₂²))
a = FR₁R₂/(I + mR₂²)