Answer: f (4c + 2) = 24c + 13
Step-by-step explanation:
Given function
f(x) = 6x + 1
Function value that is asked to find
f (4c + 2)
Substitute values into the function
f (4c + 2) = 6 (4c + 2) + 1
Expand parentheses and apply the distributive property
f (4c + 2) = 6 · 4c + 6 · 2 + 1
f (4c + 2) = 24c + 12 + 1
Combine like terms
f (4c + 2) = 24c + (12 + 1)
f (4c + 2) = [tex]\boxed{24c+13}[/tex]
Hope this helps!! :)
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