Answer:
Step-by-step explanation:
You need to use the quadratic equation
x = [tex]\frac{-b +/- \sqrt{b^2 - 4ac} }{2a}[/tex]
Givens
x = [tex]\frac{5 +/- \sqrt{5^2 - 4a*1*3} }{2} \\[/tex]
x =( 5 +/- sqrt(25 - 12) ) / 2
x = (5 +/- sqrt(13) )/2
x = (5 + sqrt(13) / 2
x = 4.303 rounded
x = (5 - sqrt(13) ) /2
x = .6972
