645 g of N₂O contains 234.55 g of oxygen.
To obtain the answer to the question given above, we'll begin by calculating the molar mass of N₂O. This can be obtained as follow:
Molar mass of N₂O = (14×2) + 16
Molar mass of N₂O = 28 + 16
Molar mass of N₂O = 44 g/mol
From the molar mass of N₂O, we can see that there are 16 g of oxygen in 44 g of N₂O.
Thus, we can obtain the mass of oxygen in 645 g of N₂O as follow:
44 g of N₂O contains 16 g of Oxygen.
Therefore,
645 g of N₂O will contain = [tex]\frac{645 * 16 }{44}\\\\[/tex] = 234.55 g of oxygen.
Hence, we can conclude that 645 g of N₂O contains 234.55 g of oxygen.
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