The given details are illustrations of addition and subtractions of fractions. The scuba driver is at an elevation of [tex]-5\frac{1}{15}[/tex] ft below the sea level.
Given that:
[tex]n_1 = 1\frac 23[/tex] --- the first dive
[tex]n_2 = 3\frac 25[/tex] ---- the additional dive
From the question, we understand that the diver starts at the sea level.
This is represented with 0ft.
So, the diver's elevation (d) is calculated as follows:
[tex]d = 0 - n_1 - n_2[/tex] --- we use subtraction because the diver is below the sea level
So, we have:
[tex]d = 0 - 1\frac 23 - 3\frac 25[/tex]
[tex]d = - 1\frac 23 - 3\frac 25[/tex]
Convert fractions
[tex]d = - \frac 53 - \frac{17}5[/tex]
Take LCM
[tex]d = \frac{-5 \times 5 - 17 \times 3}{15}[/tex]
[tex]d = \frac{-76}{15}[/tex]
Reduce fraction
[tex]d = -5\frac{1}{15}[/tex]
The above value means that the diver's elevation is at [tex]-5\frac{1}{15}[/tex] ft below the sea level.
Read more about fractions at:
https://brainly.com/question/18134643
