There is a horizontal asymptote along the x-axis at x = -1 and x = 1
What is the period of a function?
The distance between the repetition of any function is called the period of the function.
What is a odd function?
The odd functions are functions that return their negative inverse when x is replaced with –x. This means that f(x) is an odd function when f(-x) = -f(x).
What is asymptote?
An asymptote is a line that the graph of a function approaches as either x or y go to positive or negative infinity.
According to the given question.
We have a function
[tex]y = \frac{2}{x^{2} -1}[/tex]
If we draw the graph of the given function.
The graph is symmetric on y axis. So, the function is even.
Or we can also check by replacing x by -x.
[tex]f(-x) = \frac{y}{(-x)^{2}-1 }=f(x)[/tex]
Therefore, the given function is even.
In the interval (-∞, -1) and (-1, 0) the function is increasing. And in the interval {0, 1) and (1, +∞) the function is subtracting. Hence, the function is not decreasing for all the values in the domain.
There is a horizontal asymptote along the x-axis at x = -1 and x = 1.
Hence, only option III is correct.
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