There are 7 Democrats and 6 Republicans on a local city council. A planning committee of 6 for affordable housing needs to be created. Find the probability that the group is made up of at least 4 Democrats.

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Answer:

The probability is [tex]0.383[/tex].

Step-by-step explanation:

There are 7 democrats and 6 republicans  

Number of ways in which 4 democrats and 2 republicans can be selected=[tex]\[{}^{7}{{C}_{4}}\times {}^{6}{{C}_{2}}\][/tex]

Number of ways in which 5 democrats and 1 republican can be selected= [tex]\[{}^{7}{{C}_{5}}\times {}^{6}{{C}_{1}}\][/tex]

Number of ways in which 6 democrats can be selected = [tex]\[{}^{7}{{C}_{6}}\][/tex]

So, favourable outcomes are [tex]\[{}^{7}{{C}_{4}}\times {}^{6}{{C}_{2}}+{}^{7}{{C}_{5}}\times {}^{6}{{C}_{1}}+{}^{7}{{C}_{6}}\][/tex]

Total possible outcomes =[tex]\[{}^{13}{{C}_{6}}\][/tex]

Now, probability=[tex]\[\frac{Favourable}{Possible}=\frac{{}^{7}{{C}_{4}}\times {}^{6}{{C}_{2}}+{}^{7}{{C}_{5}}\times {}^{6}{{C}_{1}}+{}^{7}{{C}_{6}}}{{}^{13}{{C}_{6}}}=0.383\][/tex]

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