[tex]{\color{chartreuse}{Measure\:of\: ∠\:on\: one\: side\:of\:line\:=\:180°}}[/tex]
∠ Given are (x + 18)° , x° , 4x° and one Angle is 90° as per diagram
Let ,
1st∠ = (x + 18)°
2nd∠ = x°
3rd∠ = 4x°
so ,
[tex]⟶\:(x \:+\: 18)°\:+\:x°\:+\: 4x°\:+\:90°\:=\:180°[/tex]
[tex]⟶\:6x°\:+ \:18°\:+\:90°\:=\:180°[/tex]
[tex]⟶\:6x°\:+ \:108°\:=\:180°[/tex]
[tex]⟶\:6x°\:=\:180°\:-\:108°[/tex]
[tex]⟶\:6x\:=\:72°[/tex]
[tex]⟶\:x\:=\:\frac{72}{6} \\[/tex]
[tex]⟶\:x\:=\:12°[/tex]
substituting x = 12 at the place of x .
= x° + 18°
= 12° + 18 °
1st∠ = 30°
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= x°
2nd∠ = 12°
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= 4x°
= 4(12)°
3rd∠ = 48°
