The length of the new runway In terms of (L) is 4L.
Your question is incomplete, it seems your question is missing the following information below;
"In terms of (L) , what must be the length of the new runway?"
The given parameters;
- length of the runway, = L
- let the take off speed = V₁
For the newly designed planes;
the take off speed is double of the original = 2V₁
the acceleration for both take is constant = a
The take off speed for the given constant acceleration is given as;
[tex]v^2 = u^2 + 2as\\\\v^2 = 0 + 2as\\\\v^2 = 2as\\\\a = \frac{v^2}{2s} \\\\[/tex]
The length of the new runway In terms of (L) is calculated as follows;
[tex]a = \frac{v_1^2}{2s_1} = \frac{v_2^2}{2s_2} \\\\substitute \ the \ corresponding \ values \ for \ initial \ acceleration \ and \ new \\acceleration\\\\\frac{v_1^2}{2L} = \frac{(2v_1)^2}{2s_2}\\\\2s_2v_1^2 = 2L(4v_1^2)\\\\s_2 = \frac{2L(4v_1^2)}{2v_1^2} = \frac{8Lv_1^2}{2v_1^2} = 4L[/tex]
Thus, the length of the new runway In terms of (L) is 4L.
Learn more here: https://brainly.com/question/15206976
