The given sequence is an illustration of an arithmetic sequence, where the 12th term of the sequence is 62.
Given that:
[tex]T_1 = 18[/tex]
[tex]T_2 = 22[/tex]
First, calculate the common difference (d)
[tex]d =T_2 - T_1[/tex]
[tex]d = 22 - 18[/tex]
[tex]d = 4[/tex]
The nth term of an arithmetic sequence is:
[tex]T_n = T_1 + (n - 1) d[/tex]
So, the 12th term is:
[tex]T_{12} = 18 + (12 - 1) \times 4[/tex]
[tex]T_{12} = 18 + (11) \times 4[/tex]
[tex]T_{12} = 62[/tex]
Hence, the 12th term of the sequence is 62
Read more about arithmetic sequence at:
https://brainly.com/question/18109692
