Respuesta :
Knowing that the two naturally occurring isotopes make up the molar mass of chlorine wholly
Therefore, we can deduce that the natural abundance of another isotope would be 24.47% (1 - 75.53%)
Let x be the mass number of another isotope
Using the equation:
Relative isotopic mass x relative abundance + …… = relative atomic mass, we get:
x(24.47%) + 34.96885(75.53%) = 35.543
x = 37.31519
Therefore, the relative isotopic mass of another isotope is 37.31519 and its abundance is 24.47%
Therefore, we can deduce that the natural abundance of another isotope would be 24.47% (1 - 75.53%)
Let x be the mass number of another isotope
Using the equation:
Relative isotopic mass x relative abundance + …… = relative atomic mass, we get:
x(24.47%) + 34.96885(75.53%) = 35.543
x = 37.31519
Therefore, the relative isotopic mass of another isotope is 37.31519 and its abundance is 24.47%
