Answer:
(f * g)(x) = 8x, when x >=0
Step-by-step explanation:
I. Given f(x) = sqrt32x, g(x) = sqrt(2x)
Find (f*g) = [tex]\sqrt{32} * \sqrt{x} * \sqrt{2} *\sqrt{x}[/tex] {when [tex]\sqrt{32x} = \sqrt{32} *\sqrt{x}[/tex]
= [tex]\sqrt{32 * 2} * \sqrt{x * x}[/tex]
= [tex]\sqrt{64} * x[/tex]
(f * g) = 8x
So (f * g)(x) = 8x, when x >=0
But if your question is fog, the answer will be different.
Hope that help :)
