if a canned fish with a diameter of 76mm height of 10 mm how many numbers of cans will fit in the box with a length 36cm breath 25cm height 35cm​

Respuesta :

The number of cans that will fit the box is 694 cans.

Given:

Dimension of the cylindrical can of fish:

diameter (d) = [tex]76 mm = 7.6 cm (10 mm = 1 cm)[/tex]

radius (r) = [tex]\frac{1}{2}[/tex] of diameter = [tex]3.8 cm[/tex]

height (h) = [tex]10 mm = 1 cm[/tex]

Dimension of the box:

[tex]l = 36 cm\\b = 25cm\\h = 35cm[/tex]

Thus:

Number of cans that will fill the box = Volume of box / volume of 1 can

Volume of 1 can = volume of cylinder

Volume of cylinder = [tex]\pi r^{2} h[/tex]

Plug in the values

[tex]V = \pi \times 3.8^{2} \times 1\\V = 45.36cm^{3}[/tex]

Volume of box = [tex]l \times h \times b[/tex]

Plug in the values:

[tex]V = 36 \times 25 \times 35\\V = 31,500 cm^{3}[/tex]

Number of cans = [tex]\frac{31,500}{45.36} = 694.4[/tex]

Therefore, approximately 694 cans will fit in the box.

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