St lies on the coordinate plane with s located at (3.2). The midpoint of dt is z(3,9) state the location of the endpoint T thank you!!

The midpoint formula is just another version of the pythagorean theorem, and it states that the midpoint between (x1,y1) and (x2,y2) is [tex]\left(\frac{x_1+x_2}{2}\right),\:\left(\frac{y_1+y_2}{2}\right)[/tex]

Substituting what we know:

endpoint S is (3,2) and endpoint T is (x2,y2)

Midpoint Z is (3,9). We will apply the formula -- backwards.

[tex]\left(\frac{3+x_2}{2}\right)=3[/tex], solving with algebra we get x2 = 3

So the x-coordinate of endpoint T is 3.

[tex]\left(\frac{2+y_2}{2}\right)=9\quad[/tex], solving with algebra, we get y2 = 16.

So the y-coordinate of endpoint T is 16.

So the location of endpoint T is (3,16)