Beginning drivers soon learn that bringing an automobile to a stop requires greater distances for higher speeds. A formula that approximates the stopping distance under normal driving conditions is
d = 1.1v + 0.055v2
where v = speed of the auto in miles per hour and d = distance in feet required to bring the auto to a stop.
(a) Find the stopping distance of an auto traveling 15 mph. (Round your answer to the nearest foot.)
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(b) Find the stopping distance of an auto traveling 30 mph. (Round your answer to the nearest foot.)
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boffeemadrid boffeemadrid · Answer 1 · 2021-09-21T14:31:43+02:00

The formula for the stopping distance in feet is

[tex]d=1.1v+0.055v^2[/tex]

where [tex]v[/tex] = Speed of the car in miles per hour.

The stopping distance for the car traveling at 15 mph is

[tex]d=1.1\times 15+0.055\times 15^2\\\Rightarrow d=28.875\approx 29\ \text{feet}[/tex]

The stopping distance for the auto traveling at 15 mph is [tex]29\ \text{feet}[/tex].

The stopping distance for the car traveling at 30 mph is

[tex]d=1.1\times 30+0.055\times 30^2\\\Rightarrow d=82.5\approx 83\ \text{feet}[/tex]

The stopping distance for the auto traveling at 30 mph is [tex]83\ \text{feet}[/tex].

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