In the following problems, an equation involving x and y is given. For each problem, determine whether y is a function of x. If it is a one-to-one function, please specify and explain. If it is a function, find the domain and range.
(x - 6) = 3(y – 3)
x2 – 2x+3y = 4
y3 – 4 = 0
2|x| + |y| = 2

Respuesta :

In the following relations, y is a function of x

[tex](a)\ (x - 6) = 3(y - 3)[/tex]

[tex](b)\ x^2 - 2x + 3y = 4[/tex]

In the following relations, y is not a function of x

[tex](c)\ y^3 - 4 =0[/tex]

[tex](d)\ 2|x| + |y| = 2[/tex]

The domain and the range of each relation will be calculated using graphs (see attachment)

[tex](a)\ (x - 6) = 3(y - 3)[/tex]

Open brackets

[tex]x - 6 = 3y - 9[/tex]

Collect like terms

[tex]3y =x - 6 + 9[/tex]

[tex]3y =x +3[/tex]

Divide both sides by 3

[tex]y = \frac 13x + 1[/tex]

We have the following observations:

  • y is a function of x
  • It is a one-to-one function, because every value of x, has 1 corresponding y-value
  • The domain and the range are [tex](-\infty,\infty)[/tex]

[tex](b)\ x^2 - 2x + 3y = 4[/tex]

Rewrite as:

[tex]3y = -x^2 + 2x + 4[/tex]

Divide through by 3

[tex]y = \frac{1}{3}(-x^2 + 2x + 4)[/tex]

We have the following observations:

  • y is a function of x
  • The domain of the function is [tex](-\infty,\infty)[/tex].
  • The range of the function is [tex](-\infty, \frac 53][/tex]

[tex](c)\ y^3 - 4 =0[/tex]

Rewrite as:

[tex]y^3 = 4[/tex]

We have the following observations:

  • y is not a function of x,
  • The domain of the function is [tex](-\infty,\infty)[/tex].
  • The range of the function is [tex]\sqrt[3]4[/tex]

[tex](d)\ 2|x| + |y| = 2[/tex]

Rewrite as:

[tex]|y| = 2 - 2|x|[/tex]

We have the following observations:

  • y is not a function of x
  • The domain of the function is [tex][-1,1][/tex].
  • The range of the function is [tex][-2,2][/tex]

Read more about domain and range at:

https://brainly.com/question/1632425

Ver imagen MrRoyal