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A plumber earns $43 for a repair job, plus an additional $56 per hour he works. On Tuesday, he
completed 3 repair jobs and earned a total of more than $700.
Part A: Write an inequality that can be used to determine h, the number of hours the plumber
worked on Tuesday.

A plumber earns 43 for a repair job plus an additional 56 per hour he works On Tuesday he completed 3 repair jobs and earned a total of more than 700 Part A Wri class=

Respuesta :

norahafford

Answer:

A. 150+75h>600

B. More than 6 hours

Step-by-step explanation:

A plumber earns $50 for a repair job, so he will earn $150 for three repair jobs.

Let h be the number of hours the plumber worked on Tuesday. He earns $75 per hour worked, so he will earn $75h in h hours.

In total, the plumber earned $(150 + 75h)

A. On Tuesday, he completed 3 repair jobs and earned a total of more than $600. Thus

150+75h>600

B. Solve this inequality. Subtract 150:

150+75h-150>600-150

75h>450

Divide by 75:

h> 450/75

h>6

This means, the plumber worked more than 6 hours.

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