Use elimination.
Add the equations by columns to get the third equation,
[tex]2x+5x=7x[/tex]
[tex]3y-3y=0[/tex]
[tex]13+1=14[/tex]
The new equation has only one unknown, [tex]7x+0=14[/tex] so [tex]x=2[/tex].
Now plug in the fact that [tex]x=2[/tex] into one of the equations and solve for y (I will pick 2nd equation),
[tex]5\cdot2-3y=1[/tex]
[tex]-3y=-9\implies y=3[/tex].
The value of [tex]x=2[/tex] and [tex]y=3[/tex].
Hope this helps :)
