Option B is correct. The required expression on expansion of 20х-[2х -(х+2)-(6-x 2 )-(28 +x+x2] is 20x + 36
Expressions are function that does not include "equal" sign
Given the expression
20х-[2х -(х+2)-(6-x² )-(28 +x+x2]
Expand and collect the like terms
= 20х-[2х -х-2-6+x² -28 - x - x²]
= 20x - [x - 8 + x² - 28 - x - x² ]
x and x² cancels out from the expression to have
= 20x - [- 8 - 28]
= 20x -(-36)
= 20x + 36
Hence the required expression on expansion is 20x + 36
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