2. A F-22 Raptor has just climbed through an altitude of 9,874 m at 1,567 kph when a disk
ruptures in a sensitive piece of optical equipment. As the engineer analyzing the failure
determined the pressure differential across the sensor housing if the inside sensor pressure was
122 kPa.

Respuesta :

The pressure difference across the sensor housing will be "95 kPa".

According to the question, the values are:

Altitude,

  • 9874

Speed,

  • 1567 kph

Pressure,

  • 122 kPa

The temperature will be:

→ [tex]T = 15.04-[0.00649(9874)][/tex]

→     [tex]= 15.04-64.082[/tex]

→     [tex]= -49.042^{\circ} C[/tex]

now,

→ [tex]P_o = 101.29[\frac{(-49.042+273.1)}{288.08} ]^{(5.256)}[/tex]

→      [tex]= 27.074[/tex]

hence,

→ The pressure differential will be:

= [tex]122-27[/tex]

= [tex]95 \ kPa[/tex]

Thus the above solution is correct.

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