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What are the additive and multiplicative inverses of h(x) = x - 24?
additive inverse: j(x) = x + 24; multiplicative inverse: k(x) =
1
X-24
1
additive inverse: j(x) = = ; multiplicative inverse: k(x) = -x + 24
X-24
additive inverse:j(x) = -x + 24; multiplicative inverse: k(x) =
1
X-24
O additive inverse: j(x) = -x + 24; multiplicative inverse: k(x) = x + 24

What are the additive and multiplicative inverses of hx x 24 additive inverse jx x 24 multiplicative inverse kx 1 X24 1 additive inverse jx multiplicative inver class=

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Ajjdadon100

Answer:

Additive inverse : j(x) = -x + 24

Multiplicative inverse : k(x) = 1/x-24

Step-by-step explanation:

I literally have no idea how, I got this answer off of quizlet :) have a good day.

The additive inverse and multiplicative inverse is -x+24 and 1/x-24.

Additive Inverse and Multiplicative inverse

Additive Inverse

Additive inverse simply means changing the sign of the number and adding it to the original number to get an answer equal to 0.

Multiplicative inverse

The multiplicative inverse is a number is a value of which when multiplied by the original number, results in 1.

Given

h(x) = x - 24

To find

The additive inverse and multiplicative inverse.

How to get the additive inverse and multiplicative inverse?

h(x) = x - 24 is given,

Additive inverse simply means changing the sign of the number and adding it to the original number, then

h'(x) = -x + 24, on adding

h(x) + h'(x) = x - 24 - x + 24 = 0

The multiplicative inverse is a number is a value of which when multiplied by the original number, then

[tex]\rm h'(x) = \dfrac{1}{x - 24}[/tex], on multiplying we get,

[tex]\rm h(x) * h'(x) = (x-24)\dfrac{1}{x - 24} = 1[/tex]

The additive inverse and multiplicative inverse is -x+24 and 1/x-24.

More about the additive inverse and Multiplicative inverse

link is given below.

https://brainly.com/question/13715269

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