Part 1: A large industrial tank holds a maximum of 11,020 gallons of water. There is a drain on the bottom of the tank that allows 29 gallons per minute to drain out of the tank. Suppose the tank is full when the drain is openedHow many gallons of water are left in the tank after one minute? Two minutes ? Ten minutes? n minutes?

Respuesta :

The volumetric flow rate is represented by the symbol Q

Volume of water in the tank after one minute is 10,991 gallons

Volume of water in the tank after two minute is 10,962 gallons

Volume of water in the tank after one minute is 10,730 gallons

Volume of water in the tank after n minute is 11,020 - 29·n

The reason the above values are correct is as follows:

The given parameters are;

The volume of water the large industrial tank holds, V = 11,020 gallons

The rate of flow out of the tank through the drain on the bottom, Q = 29 gallons per minute

The initial level of water in the tank = The tank is initially filled; 11,020 gallons

Required:

The amount of water in gallons left in the tank after one minute

Solution;

The volume, [tex]V_{out}[/tex], of water that flow out of the tank after a given time, t, is given as follows;

[tex]V_{out}[/tex] = Q × t

When t = 1 minute, we have;

[tex]V_{out}[/tex] = 29 gallons/minute × 1 minute = 29 gallons

The volume of water left in the tank, [tex]V_{in \, tank}[/tex], is given as follows;

[tex]V_{in \, tank}[/tex] = V - [tex]V_{out}[/tex]

The volume left in the tank after t = 1 minute, where, [tex]V_{out}[/tex] = 29 gallons is given as follows;

After one minute, [tex]V_{in \, tank}[/tex] = 11,020 gal - 29 gal = 10,991 gal

The volume left in the tank after one minute,  [tex]V_{in \, tank}[/tex] = 10,991 gallons

Similarly, after two minutes, we have;

[tex]V_{in \, tank}[/tex] = V - [tex]V_{out}[/tex] = V - Q × t

∴ [tex]V_{in \, tank}[/tex] = 11,020 - 29 × 2 = 10,962

The number of gallons left in the tank after 2 minutes is [tex]V_{in \, tank}[/tex] = 10,962 gallons

After, t = 10 minutes, we have;

[tex]V_{in \, tank}[/tex] = V - Q × t

After ten minutes; [tex]V_{in \, tank}[/tex] = 11,020 - 29 × 10= 10,730

The number of gallons left in the tank after 10 minutes is [tex]V_{in \, tank}[/tex] = 10,730 gallons

After n minutes, we have;

t = n, therefore;

[tex]V_{in \, tank}[/tex] = 11,020 - 29 × n = 11,020 - 29·n

The number of gallons left in the tank after n minutes is [tex]V_{in \, tank}[/tex] = 11,020 - 29·n

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