The child crawled 18 meters in 823 seconds.
Given:
A child is crawling at a pace of 176 inches every 3.37 minutes.
To find:
The distance covered (in meters) by a child in 823 seconds.
Solution:
Distance covered by a child in 3.37 minutes = 176 inches
Distance covered by a child in a 1 minute = [tex]\frac{176 inches}{3.37}[/tex]
1 minute = 60 seconds
Distance covered by a child in 60 seconds = [tex]\frac{176 inches}{3.37}[/tex]
Distance covered by a child in a 1 second:
[tex]=\frac{176 inches}{3.37}\times \frac{1}{60}[/tex]
Distance covered by a child in 823 seconds:
[tex]=\frac{176 inches}{3.37}\times \frac{1}{60}\times 823=716.36 inches[/tex]
In 1 meter there are 39.37 inches.
[tex]1 meter=39.37 inches\\1 inches=\frac{1}{39.37} meters\\716.36 inches=\frac{716.36 inches}{39.37} m=18.1956 m\approx 18 m[/tex]
The child crawled 18 meters in 823 seconds.
Learn more about the unitary method here:
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