The missing values in the relationship given are :
Given the equation :
y + 5 = 4x
Value of y when x = 12 :
Put x = 12 in the equation :
y + 5 = 4(12)
y + 5 = 48
y = 48 - 5
y = 43
Value of y when x = 0
Put x = 0 in the equation :
y + 5 = 4(0)
y + 5 = 0
y = 0 - 5
y = - 5
Value of x when y = 0
Put y = 0 in the equation :
0 + 5 = 4x
-5 = 4x
Divide both sides by 4
-5/4 = x
Value of x when y = - 8
Put y = - 8 in the equation :
-8 + 5 = 4x
-3= 4x
Divide both sides by 4
-3/4= x
The missing values are : 43, - 5, - 5/4 and - 3/4
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