A combined total of $22,000 is invested in two bonds that pay 3% and 9.5% simple interest. The
annual interest is $1,765.00. How much is invested in each bond?

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Answer:

  • 9.5%: $17,000
  • 3.0%: $5,000

Step-by-step explanation:

Let x represent the amount invested at 9.5%. Then (22000-x) is the amount invested at 3%. The total interest income is ...

  0.095x +0.03(22000 -x) = 1765

  0.065x = 1105 . . . . . . . . . . . . . . . . subtract 660, simplify

  x = 17000 . . . . . . . . . . divide by 0.065

  22000 -x = 5000 . . . amount at 3%

$17,000 was invested in the 9.5% bond; $5,000 was invested in the 3% bond.