Answer:
For B :
[tex]{ \sf{b \degree + 76\degree + 90\degree = 180\degree}} \\ \{angles \: of \: a \: triangle \} \\ b\degree + 166\degree = 180\degree \\ b = 180\degree - 166\degree \\ { \boxed{ \boxed{b = 14\degree}}}[/tex]
For A :
[tex]a\degree + b\degree = 180\degree \\ \{angles \: on \: a \: straight \: line \} \\ [/tex]
but b is 14:
[tex]a + 14 = 180 \\ { \boxed{ \boxed{a = 166\degree}}}[/tex]
