Question:-
A water tank can be filled completely in 15 hours. if the tank is filled for 5½hours and left .what part of the tank is remained to be filled
Answer:-
UNITARY METHOD :-
In 15 hrs if X lts of tank is filled
then in 1hr [tex] \frac{x}{15 } lts \: is \: filled \: [/tex]
so in 5½ hrs [tex]( \frac{x}{15} \times \frac{11}{2})lts \: is \: filled \: [/tex]
Amount left to be filled :-
[tex]x - \frac{11x}{30} \\ \frac{30x - 11x}{30} \\ \frac{19x}{30} = part \: \: left \: to \: be \: filled \: [/tex]
In percentage:-
[tex] \frac{19x}{30 \times x} \times 100 \\ \frac{19 \cancel{x}}{3 \times \cancel{x}} \times 10 \\ \frac{190}{3} = 63.33\% \\ 63.33\% = \% \: left \: to \: filled \: [/tex]
