Respuesta :
The standard algorithm of multiplication is the use of partial products to calculate the products of numbers.
The product of 62865 and 17 using standard algorithm is 1068705
Given
[tex]62865 \times 17[/tex]
Using the standard algorithm, the product will be rewritten as follows:
[tex]\left\begin{array}{ccccc}6&2&8&6&5\\\times& & &1&7\end{array}\right[/tex]
Multiply 7 by 5;
The result is 35; write down 5; carry 3
[tex]\left\begin{array}{ccccc}6&2&8&6&5\\\times& & &1&7& & & & &5\end{array}\right[/tex]
Multiply 7 by 6;
The result is 42; add 42 to the previous carry (i.e. 3)
The result is 45; write down 5; carry 4
[tex]\left\begin{array}{ccccc}6&2&8&6&5\\\times& & &1&7& & & &5 &5\end{array}\right[/tex]
Multiply 7 by 8;
The result is 56; add 56 to the previous carry (i.e. 4)
The result is 60; write down 0; carry 6
[tex]\left\begin{array}{ccccc}6&2&8&6&5\\\times& & &1&7& & &0 &5 &5\end{array}\right[/tex]
Multiply 7 by 2;
The result is 14; add 14 to the previous carry (i.e. 6)
The result is 20; write down 0; carry 2
[tex]\left\begin{array}{ccccc}6&2&8&6&5\\\times& & &1&7& &0 &0 &5 &5\end{array}\right[/tex]
Multiply 7 by 6;
The result is 42; add 42 to the previous carry (i.e. 2)
The result is 44; write down 44; because we have reached the first digit
[tex]\left\begin{array}{cccccc}&6&2&8&6&5\\\times& & & &1&7\\ 4&4&0 &0 &5 &5\end{array}\right[/tex]
Multiply 1 by 5;
The result is 5; write down 5
[tex]\left\begin{array}{cccccc}&6&2&8&6&5\\\times& & & &1&7\\ 4&4&0 &0 &5 &5\\&&&&5\end{array}\right[/tex]
Multiply 1 by 6;
The result is 6; write down 6
[tex]\left\begin{array}{cccccc}&6&2&8&6&5\\\times& & & &1&7\\ 4&4&0 &0 &5 &5\\&&&6&5\end{array}\right[/tex]
Multiply 1 by 8;
The result is 8; write down 8
[tex]\left\begin{array}{cccccc}&6&2&8&6&5\\\times& & & &1&7\\ 4&4&0 &0 &5 &5\\&&8&6&5\end{array}\right[/tex]
Multiply 1 by 2;
The result is 2; write down 2
[tex]\left\begin{array}{cccccc}&6&2&8&6&5\\\times& & & &1&7\\ 4&4&0 &0 &5 &5\\&2&8&6&5\end{array}\right[/tex]
Multiply 1 by 6;
The result is 6; write down 6
[tex]\left\begin{array}{cccccc}&6&2&8&6&5\\\times& & & &1&7\\ 4&4&0 &0 &5 &5\\6&2&8&6&5\end{array}\right[/tex]
Add the calculated results;
i.e. 440055 and 628650
So, we have:
[tex]\left\begin{array}{cccccc}&6&2&8&6&5\\\times& & & &1&7\\ 4&4&0 &0 &5 &5\\6&2&8&6&5\\10&6&8&7&0&5\end{array}\right[/tex]
Hence:
[tex]62865 \times 17 =1068705[/tex]
Learn more about standard algorithm at:
https://brainly.com/question/11380840