Answer:
Not sure but I think its 4n+90)
Step-by-step explanation:
don't go with my answer to be safe
Answer:
[tex]\sum_{n=1}^{32} 2n+8 =1312[/tex]
Step-by-step explanation:
I assume you are looking for [tex]\sum_{n=1}^{32} 2n+8 \\[/tex]:
[tex]\sum_{n=1}^{32} 2n+8 \\[/tex]
[tex]\sum_{n=1}^{32} 2n+\sum_{n=1}^{32} 8 \\[/tex]
[tex]2\sum_{n=1}^{32} n+32(8)[/tex]
[tex]2(\frac{32(32+1)}{2})+256[/tex]
[tex]2(528)+256[/tex]
[tex]1056+256[/tex]
[tex]1312[/tex]
