Answer:
Step-by-step explanation:
2x-5y=8. y = 2/5x-8/5
Line q: (-6,2). Slope -5/2
y-2 = -5/2(x- - 6). y-2 = -5/2(x+6)
y-2 = - 5/2x - 6
y = -5/2x -6 +2
y = - 5/2x - 4
The equation of line 'q' is 2y + 5x + 26 = 0 and this can be determined by using the slope-intercept form of the line.
Given :
The following steps can be used in order to determine the equation of line q:
Step 1 - When the two lines are perpendicular to each other then their slopes are:
mm' = -1
Step 2 - The slope-intercept form of the line p is:
[tex]y=\dfrac{2}{5}x-\dfrac{8}{5}[/tex]
So, the slope of the line 'p' is 2/5.
Step 3 - Now, the slope of the line 'q' is given by:
m = -5/2
Step 4 - Now, the equation of line 'q' that passes through a point (-6,2) and has a slope -5/2 is given by:
[tex]y-2=-\dfrac{5}{2}(x+6)[/tex]
Step 5 - Simplify the above equation.
2y + 5x + 26 = 0
For more information, refer to the link given below:
https://brainly.com/question/11897796
