If a solution has a pH of 5, the concentration of the OH- in the solution would be 1 x [tex]10^-^9[/tex] M.
Recall that:
pH + pOH = 14
The pH is 5 in this case, hence:
5 + pOH = 14
pOH = 14 - 5
= 9
Also, recall that:
pOH = - log{OH}
Substitute pOH = 9:
9 = - log{OH}
{OH} = 1 x [tex]10^-^9[/tex] M
Therefore, the OH- concentration of a solution with a pH of 5 would be 1 x [tex]10^-^9[/tex] M
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