Answer:Thermal Energy is not a form of potential energy
Explanation:
[tex]\red{➤}\:[/tex][tex]\sf ({\frac{3}{2}})^{-1}÷ ({\frac{-2}{5}})^{-1}[/tex]
[tex]\\[/tex]
Since the power is in negetive,we write the reciprocal of the number and then solve it like positive exponents-
[tex]\begin{gathered}\\\quad\longrightarrow\quad\sf( {\dfrac{3}{2}})^{-1}÷ ({\frac{-2}{5}})^{-1}\\\end{gathered} [/tex]
[tex]\begin{gathered}\\\quad\longrightarrow\quad\sf ({\dfrac{2}{3}})^{1}÷ ({\dfrac{5}{-2}})^{1}\quad (a^1=a)\\\end{gathered} [/tex]
[tex]\begin{gathered}\\\quad\longrightarrow\quad\sf \dfrac{2}{3}÷ \dfrac{5}{(-2)}\\\end{gathered} [/tex]
[tex]\begin{gathered}\\\quad\longrightarrow\quad\sf \dfrac{2}{3}×\dfrac{(-2)}{5}\\\end{gathered} [/tex]
[tex]\begin{gathered}\\\quad\longrightarrow\quad\sf \dfrac{2×(-2)}{3×5}\\\end{gathered} [/tex]
[tex]\begin{gathered}\\\quad\longrightarrow\quad\boxed{\sf{ \dfrac{-4}{15}}}\\\end{gathered} [/tex]
Laws of Exponents-
[tex] \sf a^m×a^n = a^{m+n} \\
\sf a^m/a^n = a^{m-n} \\
\sf{(a^m)}^n = a^{mn} \\
\sf a^n/b^n = (a/b)^n \\
\sf a^0 = 1 \\
\sf a^{-m }= 1/a^m
[/tex]
