The x position will be "12 m" and the y position will be "-4.9 m".
According to the question,
Along x direction, Initial velocity:
Along x direction, Acceleration is:
Along y direction, Acceleration is:
Time,
→ The X coordinate will be:
= [tex]12\times t[/tex]
= [tex]12\times 1[/tex]
= [tex]12 \ m[/tex]
→ The Y coordinate will be:
= [tex]-(u_y t+\frac{1}{2}a_y t^2 )[/tex]
= [tex]0+4.9 t^2[/tex]
= [tex]4.9 \ t^2[/tex]
= [tex]-4.9\times 1^2[/tex]
= [tex]-4.9 \ m[/tex]
Thus the above answer is correct.
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