contestada

A duck swimming on the surface of a pond has an
initial velocity of 0.7m/s at an angle of 25° north of
west. It begins accelerating at a rate of 0.5m/s2
at an angle of 41° south of east.
Ра
W
Ducks speed
offer of seconds)

Respuesta :

From the given information:

  • Taking the movement of the Duck in the North as the x-direction
  • The movement of the Duck in the East direction as the y-direction

However, we will have to compute the initial velocity and the acceleration of the duck in their vector forms.

In vector form;

The initial velocity is:

[tex]\mathbf{u ^{\to} = 0.7 m/s ( -cos 25^0 \hat x + sin 25^0 \hat y ) \ m/s}[/tex]

The acceleration is:

[tex]\mathbf{a ^{\to} = 0.5 m/s ( cos 41^0 \hat x - sin 41^0 \hat y ) \ m/s^2}[/tex]

The objective of this question is to determine the speed of the duck at a certain time. Since it is not given, let's assume we are to determine the Duck speed after 4 seconds of accelerating;

Then, it implies that time (t) =  4 seconds.

Using the first equation of motion:

[tex]v^{\to} = u ^{\to} + a^{\to} t[/tex]

Then, we can replace their values into the equation of motion in order to determine the speed:

[tex]\mathbf{v^{\to} =\Big(0.7 ( -cos 25^0 \hat x + sin 25^0 \hat y )+4 \times 0.5 ( cos 41^0 \hat x - sin 41^0 \hat y )\Big)}[/tex]

[tex]\mathbf{v^{\to} =\Big(0.7 ( -cos 25^0 \hat x + sin 25^0 \hat y )+2.0 ( cos 41^0 \hat x - sin 41^0 \hat y )\Big)}[/tex]

[tex]\mathbf{v^{\to} =\Big( ( -0.7 cos 25^0 \hat x + 0.7 sin 25^0 \hat y )+( 2.0cos 41^0 \hat x - 2.0sin 41^0 \hat y )\Big)}[/tex]

Collect like terms:

[tex]\mathbf{v^{\to} =\Big( (2.0cos 41^0 -0.7 cos 25^0 )\hat x+( 0.7 sin 25^0 - 2.0sin 41^0 )\Big)\hat y}[/tex]

[tex]\mathbf{v^{\to} =0.87500 \hat x- 1.01629 \hat y}[/tex]

Thus, the magnitude is:

[tex]\mathbf{v^{\to} =\sqrt{(0.87500 )^2 +( 1.01629 )^2}}[/tex]

[tex]\mathbf{v^{\to} =\sqrt{0.76563 +1.03285}}[/tex]

[tex]\mathbf{v^{\to} =\sqrt{1.79848}}[/tex]

[tex]\mathbf{v^{\to} =1.34 \ m/s}[/tex]

Therefore, we can conclude that the speed of the duck after 4 seconds is 1.34 m/s

Learn more about vectors here:

https://brainly.com/question/17108011?referrer=searchResults