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There are 5 different coloured cups in a row.

The green cup is to the left of the red cup (but not necessarily next to it).
The yellow cup is to the left of the purple cup (but not necessarily next to it).
The blue cups is on one end of the row of cups.
For all these 3 statements to be true, how many different ways could these 5 cups be arranged?

Respuesta :

There are 12 possible arrangements.

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  • Considering that the blue cup has to be on one end, we consider the number of arrangements possible with the other 4 cups, then multiply by 2(considering the blue on each end).

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  • Considering green and yellow before red and purple, there are [tex]2 \times 2 = 4[/tex] outcomes(G-Y-R-P, G-Y-P-R, Y-G-R-P and Y-G-P-R).
  • Another two possible outcomes are yellow-purple and green-red, or vice-versa, thus 4 + 2 = 6 outcomes.
  • To account for the blue on the end, multiplying by 2. [tex]2 \times 6 = 12[/tex]
  • There are 12 possible arrangements.

A similar problem is given at https://brainly.com/question/24617788

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