Answer:
From general equation of a line:
[tex]y = mx + b[/tex]
m » slope, b » y-intercept.
but perpendicularly:
[tex]m _{1} \times m _{2} = - 1 \\ - 3 \times m = - 1 \\ m = \frac{1}{3} [/tex]
at point (6, 2):
[tex]2 = ( \frac{1}{3} \times 6) + b \\ 2 = 2 + b \\ b = 0[/tex]
therefore, equation is :
[tex]{ \boxed{ \boxed{y = \frac{1}{3} x}}}[/tex]