3. Find the coordinates of the midpoint of Asif A(-4, 7) and S(5,3). number 9 please

Step-by-step explanation:
slope = (x1 + x2/2 , y1 + y2/2)
x1 = -4
x2 = 5
y1 = 7
y2 = 3
after inserting the values we got,
→ ( -4 + 5/2 , 7+3/2 )
→ ( 1/2 , 10/2 )
→ ( 0.5 , 5 )
hope this answer helps you dear...take care mau u have a great day ahead!...
Answer:
( [tex]\frac{1}{2}[/tex], 5 )
Step-by-step explanation:
Given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is
( [tex]\frac{x_{1}+x_{2} }{2}[/tex] , [tex]\frac{y_{1}+y_{2} }{2}[/tex] )
Here (x₁, y₁ ) = A (- 4, 7) and (x₂, y₂ ) = B (5, 3 ) , then
midpoint = ( [tex]\frac{-4+5}{2}[/tex] , [tex]\frac{7+3}{2}[/tex] ) = ([tex]\frac{1}{2}[/tex] , [tex]\frac{10}{2}[/tex] ) = ([tex]\frac{1}{2}[/tex] , 5 )