Answer:
1.29 s
Explanation:
As we know that ,
[tex]\sf\longrightarrow Time_{descent}= \sqrt{\dfrac{2H}{g_{(moon)}}}\\\\\sf\longrightarrow t_d = \sqrt{\dfrac{ 2\times 1.4}{1.67}} \\\\\sf\longrightarrow t_d =\sqrt{1.67} s\\\\\sf\longrightarrow \boxed{\red{\sf Time_{descent}= 1.29 s }} [/tex]