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Eduard22sly

A solution with pH 4 has 10000 times the H⁺ concentration of a solution with pH 8

To obtain the answer to the question given above, we'll begin by calculating the concentration of Hydrogen ion, [H⁺] in each solution.

For solution with pH 4:

pH = 4

Concentration of Hydrogen ion [H⁺] =?

pH = –Log [H⁺]

4 = –Log [H⁺]

Multiply through by –1

–4 = Log [H⁺]

Take the antiloantilog of –4

[H⁺] = antilog (–4)

[H⁺] = 1×10¯⁴ M

For solution with pH 8:

pH = 8

Concentration of Hydrogen ion [H⁺] =?

pH = –Log [H⁺]

8 = –Log [H⁺]

Multiply through by –1

–8 = Log [H⁺]

Take the antilog of –8

[H⁺] = antilog (–8)

[H⁺] = 1×10¯⁸ M

Finally, we shall determine the ratio of the concentration of Hydrogen ion [H⁺] in solution with pH 4 to that of pH 8.

For pH 4,

Concentration of Hydrogen ion [H⁺] = 1×10¯⁴ M

For pH 8,

Concentration of Hydrogen ion [H⁺] = [H⁺] = 1×10¯⁸ M

Ratio =?

[H⁺] for pH 4 : [H⁺] for pH 8 = 1×10¯⁴ / 1×10¯⁸

[H⁺] for pH 4 / [H⁺]  pH 8 = 10000

Cross multiply

[H⁺] for pH 4 = 10000 × [H⁺] for pH 8

Therefore, we can conclude that the solution with pH 4 has 10000 times the H⁺ concentration of a solution with pH 8.

Learn more: https://brainly.com/question/15670894

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