How to do this question??

Answer:
h(2)= - 12
Step-by-step explanation:
What that means is: calculate the y-value when t=2. Where you see t, substitute 2 in the equation. y= - (2)^2 - 2(2) - 4
The answer is - 12
Answer:
-12
Step-by-step explanation:
qu. h(t) = -t^2 - 2t - 4
where h = 2
= h(t) = (-t^2)- (2^t)- (4)
= h(2) = (-2^2) - (2^2) - (4)
= (-4) - (4) - (4)
= -12
The way the brackets are done will help you when its mixed numbers and positives as the first polynomial if negative must be kept in bracket.