A 5.0 Ω, 10.0 Ω, 12.0 Ω, and 16.0 Ω resistor are connected in series to a 120 V voltage source.

What is the current of the circuit?

Group of answer choices

2.8 A

4.4 A

44 mA

28 mA

Flag question: Question 2
Question 25 pts
A 5.0 Ω, 10.0 Ω, 12.0 Ω, and 16.0 Ω resistor are connected in series to a 120 V voltage source.

What is the approximate voltage drop across each resistor?

Group of answer choices

5 V, 10 V, 12 V, and 16 V

7.5 V, 10 V, 12 V, and 24 V

22 V, 44 V, 53 V, and 70 V

14 V, 28 V, 33 V, and 45 V

Flag question: Question 3
Question 35 pts
A circuit has three resistors (R1, R2, and R3) connected in series with a voltage source. The current is measured to be a constant 1.4 A, and the voltage drop across each resistor is as follows:

VR1 = 1.7 V
VR2 = 280 mV
VR3 = 120 mV
What is the potential difference provided by the voltage source?

Group of answer choices

1.5 V

2.1 V

150 mV

210 mV

Flag question: Question 4
Question 45 pts
A circuit has three resistors (R1, R2, and R3) connected in series with a voltage source. The current is measured to be a constant 1.4 A, and the voltage drop across each resistor is as follows:

VR1 = 1.7 V
VR2 = 280 mV
VR3 = 120 mV
How much resistance is provided by R2 and R3?

Group of answer choices

39 Ω and 17 Ω

390 mΩ and 170 mΩ

200 mΩ and 86 mΩ

20 Ω and 8.6 Ω

Respuesta :

#1

[tex]\\ \bull\tt\longrightarrow R_{eq}=5+10+12+16[/tex]

[tex]\\ \bull\tt\longrightarrow R_{eq}=43\Omega[/tex]

  • V=120V

Using ohms law

[tex]\\ \bull\tt\longrightarrow I=\dfrac{V}{R}[/tex]

[tex]\\ \bull\tt\longrightarrow I=\dfrac{120}{43}[/tex]

[tex]\\ \bull\tt\longrightarrow I=2.8A[/tex]

#2

[tex]\\ \bull\tt\longrightarrow V=IR[/tex]

[tex]\\ \bull\tt\longrightarrow V_1=IR_1=2.8(5)=14V[/tex]

[tex]\\ \bull\tt\longrightarrow V_2=IR_2=2.8(10)=28V[/tex]

[tex]\\ \bull\tt\longrightarrow V_3=IR_3=2.8(12)=33V[/tex]

[tex]\\ \bull\tt\longrightarrow V_4=IR_4=2.8(16)=45V[/tex]

  • Option D

#3

  • No resistances value given hence insufficient data.
  • Click last option NOTA

#4

Make sure to attach diagram .

Insufficient data.