Given equation of the line ,
[tex]\implies 4x - 5y +(-1) = 0 [/tex]
Simplify ,
[tex]\implies 4x - 5y - 1 = 0 [/tex]
Transpose terms to RHS ,
[tex]\implies 5y = 4x - 1 [/tex]
Divide both sides by 5 ,
[tex]\implies \boxed{ y =\dfrac{4}{5}x -\dfrac{1}{5}}[/tex]
Now we know the slope intercept form of the line as [tex] y = mx + c [/tex] we have ,
- [tex] m =\dfrac{4}{5}[/tex]
As we know that the slope of all parallel lines are same . Henceforth ,
- [tex] m_{|| \ lines } =\dfrac{4}{5}[/tex]
