Karen wanted to cut three lengths of wood from a 10 foot long board. The length of three pieces she wanted to were 1 2/3 feet 2 3/4 feet and 3 5/6 feet

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Аноним Аноним · Answer 1 · 2021-10-06T16:49:06+02:00

[tex]\\ \sf\longmapsto 1\dfrac{2}{3}+2\dfrac{3}{4}+3\dfrac{5}{6}[/tex]

[tex]\\ \sf\longmapsto \dfrac{5}{3}+\dfrac{11}{4}+\dfrac{23}{6}[/tex]

[tex]\\ \sf\longmapsto \dfrac{20+33+46}{12}[/tex]

[tex]\\ \sf\longmapsto \dfrac{99}{12}[/tex]

[tex]\\ \sf\longmapsto 8.2ft[/tex]

Rope left

[tex]\\ \sf\longmapsto 10-8.2=1.8ft[/tex]

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UserIndonesia UserIndonesia · Answer 2 · 2021-10-06T17:47:53+02:00

1¾ ft ≈ 1,75 ft

[tex] \sf 1\frac{2}{3} + 2 \frac{3}{4} + 3\frac{5}{6} [/tex]

[tex] \sf = \frac{3 + 2}{3} + \frac{4 \times 2 + 3}{4} + \frac{6 \times 3 + 5}{6} [/tex]

[tex] = \sf \frac{5}{3} + \frac{11}{4} + \frac{23}{6} [/tex]

[tex] \sf = \frac{5 \times 4 + 11 \times 3}{3 \times 4} + \frac{23}{6} [/tex]

[tex] = \sf \frac{20 +33 }{12} + \frac{23}{6} [/tex]

[tex] \sf = \frac{53}{12} + \frac{23}{6} [/tex]

[tex] = \sf \frac{53}{12} + \frac{23 \times 2}{6 \times 2} [/tex]

[tex] \sf = \frac{53}{12} + \frac{46}{12} [/tex]

[tex] \sf = \frac{99}{12} [/tex]

[tex] \sf = \frac{10}{1} - \frac{99}{12} [/tex]

[tex] \sf = \frac{10 \times 12 - 99}{12} [/tex]

[tex] = \sf \frac{120 - 99}{12} [/tex]

[tex] \sf = \frac{21}{12} [/tex]

= 1¾ ft ≈ 1,75 ft