Respuesta :
I hope this helps https://www.khanacademy.org/test-prep/mcat/physical-processes/speed-and-velocity/v/calculating-average-speed-and-velocity-edited
Answer:
41.66 km/h
Explanation:
Calculate the distance of 1st travel :
v = d/t
25 km/h = d/1 h
d = 25 km/h × 1 h
- d = 25 km
Calculate the distance of 2nd travel :
v = d/t
50 km/h = d/2 h
d = 50 km/h × 2 h
- d = 100 km
Calculate the velocity of trip :
v = d/t
v = (25 + 100)/(1 + 2)
v = 125 km/3 h
- v = 41.66 km/h
So, my velocity for the trip is 41.66 km/h