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A box is in contact with a floor with a coefficient of friction of 0.50. If the box has a normal force of 500N, what force do have to push with to move the box? HELPPP

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akingbadeadeniji

Answer:

250N

Explanation:

Coefficient of friction=frictional force/Normal force

  • coefficient of friction= 0.5
  • Normal force(R)= 500N
  • Frictional force (Fr)= ?

0.5= Fr/500N

Fr= 500N×0.5 = 250N

Fr= 250N

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